행렬미분_1 \[f(\mathbf{x}) = w^T\mathbf{x} \] \[ \nabla{f} = \frac{\partial{w^T\mathbf{x}}}{\partial \mathbf{x}} = \frac{\partial{\mathbf{x}^Tw}}{\partial \mathbf{x}} = w\] proof) \[ \frac{\partial{(w^T\mathbf{x})}}{\partial \mathbf{x}} = \begin{bmatrix} \frac{\partial{(w^T\mathbf{x})}}{\partial x_1}\\ \\ \frac{\partial{(w^T\mathbf{x})}}{\partial x_2}\\ \\ \vdots \\ \\ \frac{\partial{(w^T\mathbf{x})..